PROJECTENGRAM

DIJKSTRA'S LINK STATE ALGORITHM

Dijkstra's Link State Algorithm

Tags: #◇CSNETWK #◇Computer Science #◇Computer Networks #◇Networking Protocols #◇Graph Theory Basics


◇Overview

Dijkstra's Algorithm is a "Link State" algorithm, meaning every router has a complete map of the network (the global topology) and identical link c...

◇Key Concepts

Source Node Goal Link Costs Distance Predecessor (p)

◇Details / Theory

Definition

Dijkstra's Algorithm is a "Link State" algorithm, meaning every router has a complete map of the network (the global topology) and identical link cost information. It computes the least-cost path from a single source node to all other nodes in the network.

The Logic (Iterative)

  1. Initialization: The router knows the cost to its direct neighbors. All non-neighbors are set to infinity (∞\infty).
  2. Selection: Pick the unvisited node with the smallest tentative distance.
  3. Relaxation: Check if going through this new node is cheaper than the current known path to its neighbors.
    Formula: D(v)=min⁡(D(v),D(u)+c(u,v))D(v) = \min(D(v), D(u) + c(u,v))

◇2. The Network Topology

Dijkstra Step-by-Step Edge Relaxation Execution Loop

Resulting Shortest Path Tree (SPT) Rooted at Router U

Scenario Link Costs Summary:

  • Direct Links from U: u-v = 6, u-x = 7, u-w = 9
  • Cross-Domain Links: v-w = 8, v-x = 7, x-w = 5, x-y = 4
  • Egress Links to Z: w-z = 5, y-z = 8

◇3. Problem Analysis

Question 1

What is the shortest distance to node x and what node is its predecessor? Write your answer as n,p

Analytical Breakdown:

  1. Direct Path Check: U connects directly to X with a cost of 7.

  2. Alternative Path Check: Can we beat 7?
    Path U →\rightarrow V →\rightarrow X? (Cost: 6+7=136 + 7 = 13). No.
    Path U →\rightarrow V →\rightarrow W →\rightarrow X? (Cost: 6+8+5=196 + 8 + 5 = 19). No.

  3. Conclusion: The direct link is the optimal path.
    Distance: 7
    Predecessor (p): The node immediately before X is u.

Correct Answer: 7,u

Question 2

What is the shortest distance to node v and what node is its predecessor? Write your answer as n,p

Analytical Breakdown:

  1. Direct Path Check: U connects directly to V with a cost of 6.

  2. Alternative Path Check: Can we beat 6?
    Any other path (e.g., through X) would start with a cost of 7 (U →\rightarrow X), which is already higher than 6.

  3. Conclusion: The direct link is the optimal path.
    Distance: 6
    Predecessor (p): The node immediately before V is u.

Correct Answer: 6,u

Question 3

What is the shortest distance to node z and what node is its predecessor? Write your answer as n,p

Analytical Breakdown:

This requires a multi-step search (Dijkstra's Loop).

  1. Step 0 (Start): U is at 0.

  2. Step 1 (Neighbors):
    To V: 6 (via U)
    To X: 7 (via U)
    To W: 9 (via U - Note: Diagram shows a curved link u-w with cost 9)

  3. Step 2 (Expand V): V is cheapest (6).
    V →\rightarrow W: Cost is 6+8=146 + 8 = 14. (Direct path 9 is better).

  4. Step 3 (Expand X): X is next cheapest (7).
    X →\rightarrow W: Cost is 7+5=127 + 5 = 12. (Old cost 9 is better).
    X →\rightarrow Y: Cost is 7+4=117 + 4 = 11.

  5. Step 4 (Expand W): W is next cheapest (9, via U).
    W →\rightarrow Z: Cost is 9+5=149 + 5 = 14.

  6. Step 5 (Expand Y): Y is next cheapest (11, via X).
    Y →\rightarrow Z: Cost is 11+8=1911 + 8 = 19. (Old cost 14 is better).

  7. Conclusion: The cheapest path to Z comes from W.
    Total Cost: 14
    Predecessor: w

Correct Answer: 14,w

◇Summary of Logic (Cheat Sheet)

DestinationCostPredecessorPath
X7uDirect (u-x)
V6uDirect (u-v)
Z14wu-w-z

Algorithm Tip: Always explore the node with the lowest current cost first.

◇Common Pitfalls

Not always expanding the cheapest unvisited node next — Dijkstra is a greedy algorithm. Forgetting to update (relax) neighbors when a cheaper path is found through the newly expanded node. Assuming the algorithm works with negative edge weights — it does not; use Bellman-Ford instead.

◇Summary

TL;DR — Dijkstra’s algorithm computes shortest paths from a source by greedily expanding the lowest-cost unvisited node and relaxing its neighbors. It requires non-negative edge weights and runs in O(n2)O(n^2) or O(nlog⁡n)O(n \log n) with a priority queue.

Related: - ◇Pasted image 20251121093234.png Source / Reference:

◇References & Navigation

CONFIRMATION // 理解度の確認

ACTIVE RECALL VERIFICATION

Select an answer to verify conceptual comprehension and reveal the technical rationale.

Q1

In a Link-State (LS) routing protocol such as OSPF, how do all routers in the network acquire the complete global network topology graph G=(N,E)G = (N, E) before running Dijkstra's algorithm?

Q2

In Dijkstra's algorithm initialization at source node uu, how are the initial distance values D(v)D(v) set for all other nodes v≠uv \ne u?

Q3

What is the worst-case time complexity of computing shortest paths from a single source across ∣N∣=n|N| = n nodes using Dijkstra's algorithm: (a) with a simple linear array scan for min⁡D(w)\min D(w), and (b) with a binary min-heap priority queue?

Q4

Consider a triangle graph with nodes A,B,CA, B, C and undirected link costs c(A,B)=2c(A, B) = 2, c(A,C)=8c(A, C) = 8, and c(B,C)=3c(B, C) = 3. Running Dijkstra's algorithm from source AA, what are the final shortest-path cost D(C)D(C) and predecessor p(C)p(C)?

Q5

How many messages are transmitted across the network to broadcast a single link-state change in a network with n=∣N∣n = |N| nodes and ∣E∣|E| links?