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PHYSICAL LAYER

Physical Layer

Tags: #◇Computer Science #◇CSNETWK #◇Physical Layer #◇Conceptual


◇Overview

The Physical Layer is the foundational layer responsible for transporting the raw bits that make up a data link layer frame across network media. It accepts complete frames, encodes the bits into a predefined series of signals (1s and 0s), and transmits them over the local medium. Network Interface Cards (NICs) physically connect end devices to the network media.

Fundamental Principles Physical Components: Electronic hardware devices, network adapters, connectors, and cable designs that carry signals. Encoding: The method of converting data bits into a predefined "code" or predictable pattern recognized by both sender and receiver. Signaling: The method of representing the bits physically (e.g., specific voltage levels or light pulses representing a '0' or '1').

Physical Media Types

  1. Copper Media: Transmits signals as electrical pulses.
    Issues: Suffers from attenuation (signal deterioration over distance), Electromagnetic/Radio Frequency Interference (EMI/RFI), and crosstalk (magnetic field disturbance between adjacent wires).
    Solutions: strict distance limits, shielding, and twisting wire pairs (Twisted Pair cables).
  2. Fiber-Optic Cable: Transmits signals as patterns of light pulses.
    Advantages: Supports longer distances and much higher bandwidths, experiences less attenuation, and is completely immune to EMI and RFI.
    Use Cases: Enterprise networks, Fiber-to-the-Home (FTTH), Long-Haul, and Submarine cables.
  3. Wireless Media: Transmits signals via electromagnetic radio or microwave frequencies.
    Issues: Coverage area is limited by obstacles/terrain. Susceptible to interference (microwaves, fluorescent lights), security risks, and the fact that it is a shared medium (only one device can send/receive at a time).

Wireless and Mobile Networks (IEEE 802.11 & Bluetooth)

Wireless links have unique characteristics: Free Space Path Loss (Fading): Signal strength attenuates proportionally to the square of the distance and frequency. Multipath Propagation: Radio signals reflect off objects, causing delayed overlap (pulse spreading). The coherence time is the time a bit is present in the channel, inversely proportional to frequency and receiver velocity. Noise: Interference reduces the Signal-to-Noise Ratio (SNR). Higher SNR lowers the Bit Error Rate (BER). Rate adaptation dynamically changes the transmission rate based on the SNR (slower rates have lower BERs at low SNR). Hidden Terminal Problem: Environmental attenuation may cause two nodes to be unaware of each other's transmissions, leading to collisions at the receiver. Multiple Access: 802.11 uses CSMA/CA (Collision Avoidance). It avoids collisions since collision detection is too difficult due to fading and hidden terminals. Network Modes:
Infrastructure Mode: Devices communicate with a base station / Access Point (AP). The AP coordinates access and relays traffic.
Ad-hoc Mode: No base stations; nodes communicate directly with peers. Bluetooth (PAN): Personal Area Network under 10 meters, used as a cable replacement. Uses a master/client model where the master polls clients for transmission.

◇Important Formulas

End-to-End Throughput:
The throughput is limited by the bottleneck link capacity:
Throughput=min⁡(Rc,Rs,Rbackbone)\text{Throughput} = \min(R_c, R_s, R_{backbone})
Where RcR_c is the client link rate, RsR_s is the server link rate.
Free Space Path Loss:
Path loss is proportional to the square of the frequency (ff) and the distance (dd):
Path Loss∝(f×d)2\text{Path Loss} \propto (f \times d)^2

◇Worked Examples

Example 1: Bottleneck Throughput
A server sends data over a link with capacity Rs=100 MbpsR_s = 100 \text{ Mbps}. The client receives data over an access link with capacity Rc=15 MbpsR_c = 15 \text{ Mbps}. There is a shared backbone with capacity R=1 GbpsR = 1 \text{ Gbps} serving 10 equal connections.
The per-connection share of the backbone is 1000 Mbps/10=100 Mbps1000 \text{ Mbps} / 10 = 100 \text{ Mbps}.
Throughput = min⁡(100,15,100)=15 Mbps\min(100, 15, 100) = 15 \text{ Mbps}. The client's access link is the bottleneck.

◇References & Navigation

CONFIRMATION // 理解度の確認

ACTIVE RECALL VERIFICATION

Select an answer to verify conceptual comprehension and reveal the technical rationale.

Q1

What are the three main physical Impairments that degrade signals traveling across guided copper media (such as Unshielded Twisted Pair — UTP)?

Q2

Why are the insulated copper wires inside a Cat5e/Cat6 Ethernet cable twisted together in pairs?

Q3

What are the primary physical advantages of Single-Mode and Multi-Mode Optical Fiber over copper twisted-pair cabling for long-haul backbone links?

Q4

In wireless physical-layer transmission (IEEE 802.11 Wi-Fi), how does Rate Adaptation respond when a mobile user walks farther away from the Access Point and the Signal-to-Noise Ratio (SNR) drops?

Q5

In IEEE 802.11 wireless networks, what is the difference between Infrastructure Mode and Ad-Hoc Mode?

Physical Layer | PROJECT ENGRAM